1/5x^2-2x+5=0

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Solution for 1/5x^2-2x+5=0 equation:


x in (-oo:+oo)

(1/5)*x^2-(2*x)+5 = 0

(1/5)*x^2-2*x+5 = 0

1/5*x^2-2*x+5 = 0

DELTA = (-2)^2-(1/5*4*5)

DELTA = 0

x = 2/(1/5*2)

x = 5 or x = 5

x in { 5, 5 }

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